19th Recursive prime in the form of p[k+1]=l(k+1)*(m[k]^2-n[k]^2)+/-1, while p[k]=m[k]+n[k]
Define: p[1] = m[1] + n[1] = 2 + 1 p[2](l=2) = 2*(m[1]^2-n[1]^2)-1 = 2*(4-1)-1 = 5 = 2^3 – 3 p[3](l=2) = 2*(2^6-3^2)-1 = 2^7 – 19 p[4](l=4) = 4*(2^14 – 19^2) -1 = 2^16 – 1445 p[5](l=8) = 8*(2^32 – 1445^2) +1 = 2^35 – 16704199 p[6](l=18) = 2^71*3^2 – (16704199^2*18+1) p[7](l=84) = […]
